What is the derivative of 4x^4+2x^3-x+1 ?

The derivative of 4x^4+2x^3-x+1 is 16x^3+6x^2-1

What is the first derivative of 4x^4+2x^3-x+1 ?

The first derivative of 4x^4+2x^3-x+1 is 16x^3+6x^2-1

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\frac{d}{d x} (4 x^{4} + 2 x^{3} - x + 1)

16 x^{3} + 6 x^{2} - 1

Solution steps

\frac{d}{d x} (4 x^{4} + 2 x^{3} - x + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x^{4}) + \frac{d}{d x} (2 x^{3}) - \frac{d x}{d x} + \frac{d}{d x} (1)

\frac{d}{d x} (4 x^{4}) = 16 x^{3}

\frac{d}{d x} (2 x^{3}) = 6 x^{2}

\frac{d x}{d x} = 1

\frac{d}{d x} (1) = 0

= 16 x^{3} + 6 x^{2} - 1 + 0

Simplify

= 16 x^{3} + 6 x^{2} - 1

\int sin^{2} (n x) d x

y = \frac{( x + b ) ( x - a )}{( x - b )}

\int e^{(x - y)} d y

\int t \cdot sec^{2} (2 t) d t

What is the derivative of 4x^4+2x^3-x+1 ?
The derivative of 4x^4+2x^3-x+1 is 16x^3+6x^2-1
What is the first derivative of 4x^4+2x^3-x+1 ?
The first derivative of 4x^4+2x^3-x+1 is 16x^3+6x^2-1