What is (\partial)/(\partial x)(-xyz^2+6) ?

The answer to (\partial)/(\partial x)(-xyz^2+6) is -yz^2

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(\partial)/(\partial x)(-xyz^2+6)

\frac{\partial}{\partial x} (- x y z^{2} + 6)

- y z^{2}

Solution steps

\frac{\partial}{\partial x} (- x y z^{2} + 6)

Treat

y, z

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{\partial}{\partial x} (x y z^{2}) + \frac{\partial}{\partial x} (6)

\frac{\partial}{\partial x} (x y z^{2}) = y z^{2}

\frac{\partial}{\partial x} (6) = 0

= - y z^{2} + 0

Simplify

= - y z^{2}

\frac{d}{d x} (x sin (π) x)

x \to 0 + lim (x ln (x^{3}))

\frac{\partial}{\partial x} (\frac{2 x ^{2}}{y ^{2} + x ^{2}})

\int_{- 1}^{3} 2 x + 3 - x^{2} d x

\frac{d}{d x} ((arctan (6 x))^{2})

What is (\partial)/(\partial x)(-xyz^2+6) ?
The answer to (\partial)/(\partial x)(-xyz^2+6) is -yz^2