What is the integral of x^{28}e^{x^{29}} ?

The integral of x^{28}e^{x^{29}} is 1/29 e^{x^{29}}+C

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integral of x^{28}e^{x^{29}}

\int x^{28} e^{x^{29}} d x

\frac{1}{29} e^{x^{29}} + C

Solution steps

\int x^{28} e^{x^{29}} d x

Apply u-substitution

: \int \frac{1}{29} d u

= \int \frac{1}{29} d u

Integral of a constant:

\int a d x = a x

= \frac{1}{29} u

Substitute back

u = e^{x^{29}}

= \frac{1}{29} e^{x^{29}}

Add a constant to the solution

= \frac{1}{29} e^{x^{29}} + C

\int ln (\frac{1 - x}{1 + x}) d x

\frac{d ^{2}}{d x ^{2}} (3 e^{- x^{2}})

\frac{d}{d x} (\frac{20 sin ( tw )}{tw})

y = - 5 - 8 x^{2}, (- 3, - 77)

x \frac{d y}{d x} + y = 11 x

What is the integral of x^{28}e^{x^{29}} ?
The integral of x^{28}e^{x^{29}} is 1/29 e^{x^{29}}+C