What is the integral of cos(3z+4) ?

The integral of cos(3z+4) is 1/3 sin(3z+4)+C

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integral of cos(3z+4)

\int cos (3 z + 4) d z

\frac{1}{3} sin (3 z + 4) + C

Solution steps

\int cos (3 z + 4) d z

Apply u-substitution

: \int cos (u) \frac{1}{3} d u

= \int cos (u) \frac{1}{3} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{3} \cdot \int cos (u) d u

Use the common integral:

\int cos (u) d u = sin (u)

= \frac{1}{3} sin (u)

Substitute back

u = 3 z + 4

= \frac{1}{3} sin (3 z + 4)

Add a constant to the solution

= \frac{1}{3} sin (3 z + 4) + C

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\int_{- 1}^{1} 1.5 x^{4} d x

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What is the integral of cos(3z+4) ?
The integral of cos(3z+4) is 1/3 sin(3z+4)+C