What is the d/(dθ)(θcos(θ)-sin(θ)) ?

The d/(dθ)(θcos(θ)-sin(θ)) is -θsin(θ)

What is the first d/(dθ)(θcos(θ)-sin(θ)) ?

The first d/(dθ)(θcos(θ)-sin(θ)) is -θsin(θ)

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\frac{d}{d θ} (θ cos (θ) - sin (θ))

- θ sin (θ)

Solution steps

\frac{d}{d θ} (θ cos (θ) - sin (θ))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d θ} (θ cos (θ)) - \frac{d}{d θ} (sin (θ))

\frac{d}{d θ} (θ cos (θ)) = cos (θ) - θ sin (θ)

\frac{d}{d θ} (sin (θ)) = cos (θ)

= cos (θ) - θ sin (θ) - cos (θ)

Simplify

= - θ sin (θ)

\frac{d}{d x} (e^{x + 2 y})

\frac{d}{d x} (ln (\frac{( 2 x - 1 )}{x - 1}))

\int e^{s i n (x)} \cdot cos (x) d x

\int \frac{x - 11}{x ^{2} + 3 x - 4} d x

n = 0 \sum \infty \frac{4 ^{n}}{n !}

What is the d/(dθ)(θcos(θ)-sin(θ)) ?
The d/(dθ)(θcos(θ)-sin(θ)) is -θsin(θ)
What is the first d/(dθ)(θcos(θ)-sin(θ)) ?
The first d/(dθ)(θcos(θ)-sin(θ)) is -θsin(θ)