What is the derivative of 4/(x-4)+(27)/(2x+2) ?

The derivative of 4/(x-4)+(27)/(2x+2) is (-35x^2+200x-440)/(2(x-4)^2(x+1)^2)

What is the first derivative of 4/(x-4)+(27)/(2x+2) ?

The first derivative of 4/(x-4)+(27)/(2x+2) is (-35x^2+200x-440)/(2(x-4)^2(x+1)^2)

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derivative of

\frac{4}{x - 4} + \frac{27}{2 x + 2}

\frac{- 35 x ^{2} + 200 x - 440}{2 ( x - 4 ) ^{2} ( x + 1 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{4}{x - 4} + \frac{27}{2 x + 2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{4}{x - 4}) + \frac{d}{d x} (\frac{27}{2 x + 2})

\frac{d}{d x} (\frac{4}{x - 4}) = - \frac{4}{( x - 4 ) ^{2}}

\frac{d}{d x} (\frac{27}{2 x + 2}) = - \frac{27}{2 ( x + 1 ) ^{2}}

= - \frac{4}{( x - 4 ) ^{2}} - \frac{27}{2 ( x + 1 ) ^{2}}

Simplify

- \frac{4}{( x - 4 ) ^{2}} - \frac{27}{2 ( x + 1 ) ^{2}} : \frac{- 35 x ^{2} + 200 x - 440}{2 ( x - 4 ) ^{2} ( x + 1 ) ^{2}}

= \frac{- 35 x ^{2} + 200 x - 440}{2 ( x - 4 ) ^{2} ( x + 1 ) ^{2}}

x^{^{'}} - x = 0

\frac{\partial}{\partial x} (ln (x^{2} + y x))

10 - 7 x, x^{2} - 20, x = 0

(- 25, - 75), (- 13, - 60)

\int q^{5} ln (5 q) d q

What is the derivative of 4/(x-4)+(27)/(2x+2) ?
The derivative of 4/(x-4)+(27)/(2x+2) is (-35x^2+200x-440)/(2(x-4)^2(x+1)^2)
What is the first derivative of 4/(x-4)+(27)/(2x+2) ?
The first derivative of 4/(x-4)+(27)/(2x+2) is (-35x^2+200x-440)/(2(x-4)^2(x+1)^2)