What is (\partial)/(\partial x)(60-x^2y^3) ?

The answer to (\partial)/(\partial x)(60-x^2y^3) is -2xy^3

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(\partial)/(\partial x)(60-x^2y^3)

\frac{\partial}{\partial x} (60 - x^{2} y^{3})

- 2 x y^{3}

Solution steps

\frac{\partial}{\partial x} (60 - x^{2} y^{3})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (60) - \frac{\partial}{\partial x} (x^{2} y^{3})

\frac{\partial}{\partial x} (60) = 0

\frac{\partial}{\partial x} (x^{2} y^{3}) = 2 y^{3} x

= 0 - 2 y^{3} x

Simplify

= - 2 x y^{3}

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What is (\partial)/(\partial x)(60-x^2y^3) ?
The answer to (\partial)/(\partial x)(60-x^2y^3) is -2xy^3