What is the derivative of 3x+sqrt(x) ?

The derivative of 3x+sqrt(x) is 3+1/(2sqrt(x))

What is the first derivative of 3x+sqrt(x) ?

The first derivative of 3x+sqrt(x) is 3+1/(2sqrt(x))

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derivative of

3 x + x

3 + \frac{1}{2 x}

Solution steps

\frac{d}{d x} (3 x + x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x) + \frac{d}{d x} (x)

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (x) = \frac{1}{2 x}

= 3 + \frac{1}{2 x}

\frac{\partial}{\partial u} (\frac{u - v}{u + v})

\int_{0}^{2} (8 t i - t^{3} j + 3 t^{5} k) d t

\int \frac{e ^{\frac{1}{x ^{9}}}}{x ^{10}} d x

x \to 6 lim (\frac{( x ^{5} - 7776 )}{x - 6})

\int 8 x 4 x^{2} + 5 d x

What is the derivative of 3x+sqrt(x) ?
The derivative of 3x+sqrt(x) is 3+1/(2sqrt(x))
What is the first derivative of 3x+sqrt(x) ?
The first derivative of 3x+sqrt(x) is 3+1/(2sqrt(x))