What is the derivative of 4/(x^2+4) ?

The derivative of 4/(x^2+4) is -(8x)/((x^2+4)^2)

What is the first derivative of 4/(x^2+4) ?

The first derivative of 4/(x^2+4) is -(8x)/((x^2+4)^2)

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derivative of

\frac{4}{x ^{2} + 4}

- \frac{8 x}{( x ^{2} + 4 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{4}{x ^{2} + 4})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d}{d x} (\frac{1}{x ^{2} + 4})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 4 \frac{d}{d x} ((x^{2} + 4)^{- 1})

Apply the chain rule:

- \frac{1}{( x ^{2} + 4 ) ^{2}} \frac{d}{d x} (x^{2} + 4)

= - \frac{1}{( x ^{2} + 4 ) ^{2}} \frac{d}{d x} (x^{2} + 4)

\frac{d}{d x} (x^{2} + 4) = 2 x

= 4 (- \frac{1}{( x ^{2} + 4 ) ^{2}} \cdot 2 x)

Simplify

4 (- \frac{1}{( x ^{2} + 4 ) ^{2}} \cdot 2 x) : - \frac{8 x}{( x ^{2} + 4 ) ^{2}}

= - \frac{8 x}{( x ^{2} + 4 ) ^{2}}

\frac{d y}{d x} = e^{- y} cos (x)

\int 9 sin^{3} (x co) s^{2} x d x

\frac{2 u ^{2}}{( u ^{2} + u ) ^{3}}

\int \frac{1}{( 3 x ) ^{2}} d x

\int_{0}^{6} π (3)^{2} d x

What is the derivative of 4/(x^2+4) ?
The derivative of 4/(x^2+4) is -(8x)/((x^2+4)^2)
What is the first derivative of 4/(x^2+4) ?
The first derivative of 4/(x^2+4) is -(8x)/((x^2+4)^2)