What is the limit as x approaches+0 of 1/x ?

The limit as x approaches+0 of 1/x is diverges

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limit as x approaches+0 of 1/x

x \to + 0 lim (\frac{1}{x})

diverges

Solution steps

x \to 0 lim (\frac{1}{x})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (\frac{1}{x}) = \infty

x \to 0 - lim (\frac{1}{x}) = - \infty

= diverges

y^{^{'}} - \frac{7}{x} y = \frac{y ^{5}}{x ^{5}}

e^{5 (t - 2)}

\frac{1}{3} π r^{2} h

\int_{0}^{3} x^{2} + 9 d x

\frac{d}{d x} (\frac{1}{4 x ^{2}})

What is the limit as x approaches+0 of 1/x ?
The limit as x approaches+0 of 1/x is diverges