What is the integral from 0 to infinity of sin(7x) ?

The integral from 0 to infinity of sin(7x) is diverges

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integral from 0 to infinity of sin(7x)

\int_{0}^{\infty} sin (7 x) d x

diverges

Solution steps

\int_{0}^{\infty} sin (7 x) d x

Compute the indefinite integral:

\int sin (7 x) d x = - \frac{1}{7} cos (7 x) + C

Compute the boundaries:

\int_{0}^{\infty} sin (7 x) d x =

diverges

= diverges

\int - \frac{3}{2} x^{2} + 3 x^{4} - 2 d x

\frac{d}{d x} (\frac{1}{2} sec (x) - \frac{1}{3} csc (x))

\int \frac{2}{3} x d x

\frac{d}{d x} (14 x)

t^{2} y^{^{'}} + t y = 4, y (1) = 3

What is the integral from 0 to infinity of sin(7x) ?
The integral from 0 to infinity of sin(7x) is diverges