What is the tangent of f(x)=x^2-7,(5,18) ?

The tangent of f(x)=x^2-7,(5,18) is y=10x-32

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tangent of f(x)=x^2-7,(5,18)

tangent of

f (x) = x^{2} - 7, (5, 18)

y = 10 x - 32

Solution steps

Find the slope of

f (x) = x^{2} - 7 : \frac{df ( x )}{d x} = 2 x

Compute the slope of

f (x) = x^{2} - 7

(5, 18) : m = 10

Find the line with slope m=

10

and passing through

(5, 18) : y = 10 x - 32

y = 10 x - 32

x \to 4 lim (5 x - 2)

\int \frac{3}{x ( x ^{4} + 8 )} d x

y^{^{'}} + 9 (tan (9 x)) y = - cos (9 x)

\frac{\partial}{\partial y} (ln (x^{2} + x y))

What is the tangent of f(x)=x^2-7,(5,18) ?
The tangent of f(x)=x^2-7,(5,18) is y=10x-32