What is (\partial)/(\partial y)(x^2-xyz) ?

The answer to (\partial)/(\partial y)(x^2-xyz) is -xz

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial y)(x^2-xyz)

\frac{\partial}{\partial y} (x^{2} - x yz)

- x z

Solution steps

\frac{\partial}{\partial y} (x^{2} - x yz)

Treat

x, z

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (x^{2}) - \frac{\partial}{\partial y} (x yz)

\frac{\partial}{\partial y} (x^{2}) = 0

\frac{\partial}{\partial y} (x yz) = x z

= 0 - x z

Simplify

= - x z

\int e^{3 x} - \frac{1}{( x + 4 ) ^{2}} d x

\int \frac{1}{x ( ln ( x ^{6} ) ) ^{8}} d x

\int \frac{2 x ^{1}}{( x ^{5} ) ^{3}} d x

\int \frac{1}{x} + \frac{1}{2 - x} d x

x^{2} + 1, - 2, - 2, 2

What is (\partial)/(\partial y)(x^2-xyz) ?
The answer to (\partial)/(\partial y)(x^2-xyz) is -xz