What is the tangent of g(x)=e^{x^5},(-1, 1/e) ?

The tangent of g(x)=e^{x^5},(-1, 1/e) is y= 5/e x+6/e

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tangent of g(x)=e^{x^5},(-1, 1/e)

tangent of

g (x) = e^{x^{5}}, (- 1, \frac{1}{e})

y = \frac{5}{e} x + \frac{6}{e}

Solution steps

Find the slope of

g (x) = e^{x^{5}} : \frac{d g ( x )}{d x} = e^{x^{5}} \cdot 5 x^{4}

Compute the slope of

g (x) = e^{x^{5}}

(- 1, \frac{1}{e}) : m = \frac{5}{e}

Find the line with slope m=

\frac{5}{e}

and passing through

(- 1, \frac{1}{e}) : y = \frac{5}{e} x + \frac{6}{e}

y = \frac{5}{e} x + \frac{6}{e}

\frac{\partial}{\partial x} (2 ln (x))

t^{2} e^{2 t}

b \to \infty lim (b c)

\int \frac{1}{5 + 3 x ^{2}} d x

24 x - 4 x

What is the tangent of g(x)=e^{x^5},(-1, 1/e) ?
The tangent of g(x)=e^{x^5},(-1, 1/e) is y= 5/e x+6/e