What is (\partial)/(\partial y)(x-2y+2z) ?

The answer to (\partial)/(\partial y)(x-2y+2z) is -2

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(\partial)/(\partial y)(x-2y+2z)

\frac{\partial}{\partial y} (x - 2 y + 2 z)

- 2

Solution steps

\frac{\partial}{\partial y} (x - 2 y + 2 z)

Treat

x, z

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (x) - \frac{\partial}{\partial y} (2 y) + \frac{\partial}{\partial y} (2 z)

\frac{\partial}{\partial y} (x) = 0

\frac{\partial}{\partial y} (2 y) = 2

\frac{\partial}{\partial y} (2 z) = 0

= 0 - 2 + 0

Simplify

= - 2

\frac{d}{d t} (\frac{t - t}{t ^{\frac{1}{9}}})

\frac{\partial}{\partial y} (2 cos (y))

\int 2 e^{θ} d θ

(\frac{1}{x ^{2}} - \frac{3}{x ^{4}}) (x + 5 x^{3})

f (x) = \frac{2}{x - 4}

What is (\partial)/(\partial y)(x-2y+2z) ?
The answer to (\partial)/(\partial y)(x-2y+2z) is -2