What is the tangent of f(x)=xcos(x),\at x=(3pi)/2 ?

The tangent of f(x)=xcos(x),\at x=(3pi)/2 is y=(3pi)/2 x-(9pi^2)/4

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tangent of f(x)=xcos(x),\at x=(3pi)/2

tangent of

f (x) = x cos (x), at x = \frac{3 π}{2}

y = \frac{3 π}{2} x - \frac{9 π ^{2}}{4}

Solution steps

Find the tangent point:

(\frac{3 π}{2}, 0)

Find the slope of

f (x) = x cos (x) : \frac{df ( x )}{d x} = cos (x) - x sin (x)

Compute the slope of

f (x) = x cos (x)

x = \frac{3 π}{2} : m = \frac{3 π}{2}

Find the line with slope m=

\frac{3 π}{2}

and passing through

(\frac{3 π}{2}, 0) : y = \frac{3 π}{2} x - \frac{9 π ^{2}}{4}

y = \frac{3 π}{2} x - \frac{9 π ^{2}}{4}

\int 4 sec (x) tan (x) d x

\frac{d}{d x} (\frac{13}{x})

\frac{1}{( s ^{2} - 1 ) ^{2}}

\int_{1}^{3} \frac{2 t ^{2} + 1}{t} d t

\int \frac{3 sin ( x )}{cos ^{3} ( x )} d x

What is the tangent of f(x)=xcos(x),\at x=(3pi)/2 ?
The tangent of f(x)=xcos(x),\at x=(3pi)/2 is y=(3pi)/2 x-(9pi^2)/4