What is the tangent of y=4-2x^2 ?

The tangent of y=4-2x^2 is y=-4a_{0}x+4+2a_{0}^2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of y=4-2x^2

tangent of

y = 4 - 2 x^{2}

y = - 4 a_{0} x + 4 + 2 a_{0}^{2}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, 4 - 2 a_{0}^{2})

Find the slope of

y = 4 - 2 x^{2} : \frac{d y}{d x} = - 4 x

Compute the slope of

y = 4 - 2 x^{2}

x = a_{0} : m = - 4 a_{0}

Find the line with slope m=

- 4 a_{0}

and passing through

(a_{0}, 4 - 2 a_{0}^{2}) : y = - 4 a_{0} x + 4 + 2 a_{0}^{2}

y = - 4 a_{0} x + 4 + 2 a_{0}^{2}

u + 1

\frac{\partial}{\partial x} (x^{3} + y^{5} + x^{7} - y^{2})

\frac{\partial}{\partial x} (A x)

\frac{d}{d x} (\frac{e ^{- x} cos ^{2} ( x )}{x ^{2} + x + 1})

\frac{\partial}{\partial x} (\frac{v}{x})

What is the tangent of y=4-2x^2 ?
The tangent of y=4-2x^2 is y=-4a_{0}x+4+2a_{0}^2