What is the derivative of 2x^3-3x^2-5 ?

The derivative of 2x^3-3x^2-5 is 6x^2-6x

What is the first derivative of 2x^3-3x^2-5 ?

The first derivative of 2x^3-3x^2-5 is 6x^2-6x

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\frac{d}{d x} (2 x^{3} - 3 x^{2} - 5)

6 x^{2} - 6 x

Solution steps

\frac{d}{d x} (2 x^{3} - 3 x^{2} - 5)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{3}) - \frac{d}{d x} (3 x^{2}) - \frac{d}{d x} (5)

\frac{d}{d x} (2 x^{3}) = 6 x^{2}

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (5) = 0

= 6 x^{2} - 6 x - 0

Simplify

= 6 x^{2} - 6 x

f (x) = 5 cos^{2} (x)

x \to 2 lim (2 - x)

\int \frac{ln ( x )}{x ^{3} ( ln ( x ) - 1 ) ^{3}} d x

\frac{d ^{2}}{d x ^{2}} (\frac{1}{x ^{11}})

x^{3} - 5 x

What is the derivative of 2x^3-3x^2-5 ?
The derivative of 2x^3-3x^2-5 is 6x^2-6x
What is the first derivative of 2x^3-3x^2-5 ?
The first derivative of 2x^3-3x^2-5 is 6x^2-6x