What is (\partial)/(\partial v)(u+uv) ?

The answer to (\partial)/(\partial v)(u+uv) is u

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(\partial)/(\partial v)(u+uv)

\frac{\partial}{\partial v} (u + uv)

u

Solution steps

\frac{\partial}{\partial v} (u + uv)

Treat

u

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial v} (u) + \frac{\partial}{\partial v} (uv)

\frac{\partial}{\partial v} (u) = 0

\frac{\partial}{\partial v} (uv) = u

= 0 + u

Simplify

= u

y = x^{3} - 8 x^{2} + 4 x - 32

\int \frac{1}{sin ( y )} d y

\int sin (x) sec (x) d x

\frac{d}{d x} (sin (x) \cdot tan (x))

\frac{d x}{d t} = a x - b x^{2} - 0

What is (\partial)/(\partial v)(u+uv) ?
The answer to (\partial)/(\partial v)(u+uv) is u