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Popular >

y^'=2(y^2+1)

Solution

y^{^{'}} = 2 (y^{2} + 1)

Solution

y = tan (2 t + c_{1})

Solution steps

y^{'} (t) = 2 (y^{2} + 1)

Solve separable ODE:

y = tan (2 t + c_{1})

y = tan (2 t + c_{1})

Popular Examples

derivative of x^2-xy=7

\frac{d}{d x} (x^{2} - x y) = 7

derivative of-1/(1+y^2-cos(x)+2xy)

\frac{d}{d x} (- \frac{1}{1 + y ^{2}} - cos (x) + 2 x y)

derivative of (sqrt(x))/(9+x)derivative of

\frac{x}{9 + x}

limit as x approaches 1 of (x-1)/(1-x^2)

x \to 1 lim (\frac{x - 1}{1 - x ^{2}})

integral of x^4sin(2x)

\int x^{4} sin (2 x) d x

Frequently Asked Questions (FAQ)

What is the solution for y^'=2(y^2+1) ?
The solution for y^'=2(y^2+1) is y=tan(2t+c_{1})