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Popular >

f^'(t)=(8t)/(8+sqrt(t))

Solution

f^{^{'}} (t) = \frac{8 t}{8 + t}

Solution

f (t) = 16 (\frac{1}{3} t^{\frac{3}{2}} - 4 t + 64 t - 512 ln (t + 8)) + c_{1}

Solution steps

f^{'} (t) = \frac{8 t}{8 + t}

If

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

f (t) = \int \frac{8 t}{8 + t} d t

\int \frac{8 t}{8 + t} d t = 16 (\frac{1}{3} t^{\frac{3}{2}} - 4 t + 64 t - 512 ln (t + 8)) + c_{1}

f (t) = 16 (\frac{1}{3} t^{\frac{3}{2}} - 4 t + 64 t - 512 ln (t + 8)) + c_{1}

Popular Examples

derivative of f(x)=(2x^2-1)^{1/2}derivative of

f (x) = (2 x^{2} - 1)^{\frac{1}{2}}

y^{''}+8y^'+65y=0,y(0)=0,y^'(0)=0

y^{^{''}} + 8 y^{^{'}} + 65 y = 0, y (0) = 0, y^{^{'}} (0) = 0

limit as x approaches-2 of x^2-2x^2+2x+3

x \to - 2 lim (x^{2} - 2 x^{2} + 2 x + 3)

derivative of (tan(x-1)/(sec(x)))

\frac{d}{d x} (\frac{tan ( x ) - 1}{sec ( x )})

integral of 8/(x^2-1)

\int \frac{8}{x ^{2} - 1} d x

Frequently Asked Questions (FAQ)

What is the solution for f^'(t)=(8t)/(8+sqrt(t)) ?
The solution for f^'(t)=(8t)/(8+sqrt(t)) is f(t)=16(1/3 t^{3/2}-4t+64sqrt(t)-512ln(sqrt(t)+8))+c_{1}