What is the integral from 0 to 1 of pi(y-y^4) ?

The integral from 0 to 1 of pi(y-y^4) is pi 3/10

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integral from 0 to 1 of pi(y-y^4)

\int_{0}^{1} π (y - y^{4}) d y

π \frac{3}{10}

Decimal Notation

0.94247 \dots

Solution steps

\int_{0}^{1} π (y - y^{4}) d y

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= π \cdot \int_{0}^{1} y - y^{4} d y

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= π (\int_{0}^{1} y d y - \int_{0}^{1} y^{4} d y)

\int_{0}^{1} y d y = \frac{1}{2}

\int_{0}^{1} y^{4} d y = \frac{1}{5}

= π (\frac{1}{2} - \frac{1}{5})

Join

\frac{1}{2} - \frac{1}{5} : \frac{3}{10}

= π \frac{3}{10}

\int \frac{4 x + 6}{( x ^{2} + 3 x + 7 ) ^{3}} d x

\frac{x ^{5}}{8}

\frac{10}{s}

x \to \infty lim (1.0 2^{x})

\int \frac{1}{x ^{2} + 2 x} d x

What is the integral from 0 to 1 of pi(y-y^4) ?
The integral from 0 to 1 of pi(y-y^4) is pi 3/10