What is the derivative of 2sin(x)cos(x) ?

The derivative of 2sin(x)cos(x) is cos(2x)*2

What is the first derivative of 2sin(x)cos(x) ?

The first derivative of 2sin(x)cos(x) is cos(2x)*2

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derivative of

2 sin (x) cos (x)

cos (2 x) \cdot 2

Solution steps

\frac{d}{d x} (2 sin (x) cos (x))

Simplify

2 sin (x) cos (x) : sin (2 x)

= \frac{d}{d x} (sin (2 x))

Apply the chain rule:

cos (2 x) \frac{d}{d x} (2 x)

= cos (2 x) \frac{d}{d x} (2 x)

\frac{d}{d x} (2 x) = 2

= cos (2 x) \cdot 2

\frac{d y}{d x} = y, y (7) = 8

\frac{\partial}{\partial y} (sin (3 x) cos (3 y))

\frac{( e ^{\frac{b}{x}} )}{( e ^{\frac{b}{x}} - 1 )}

\frac{d}{d x} ((x^{2} sin (x))^{5})

\int \frac{e ^{x}}{x + 1} d x

What is the derivative of 2sin(x)cos(x) ?
The derivative of 2sin(x)cos(x) is cos(2x)*2
What is the first derivative of 2sin(x)cos(x) ?
The first derivative of 2sin(x)cos(x) is cos(2x)*2