What is (\partial)/(\partial x)(2y^2+3x) ?

The answer to (\partial)/(\partial x)(2y^2+3x) is 3

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(\partial)/(\partial x)(2y^2+3x)

\frac{\partial}{\partial x} (2 y^{2} + 3 x)

3

Solution steps

\frac{\partial}{\partial x} (2 y^{2} + 3 x)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (2 y^{2}) + \frac{\partial}{\partial x} (3 x)

\frac{\partial}{\partial x} (2 y^{2}) = 0

\frac{\partial}{\partial x} (3 x) = 3

= 0 + 3

Simplify

= 3

\int \frac{x ^{10}}{x ^{2} + x - 2} d x

\int \frac{x ^{2}}{( x ^{3} - 2 ) ^{3}} d x

\frac{d}{d x} (\frac{8 x ^{2} + 4 x + 8}{x})

4 x^{3}, at x = 1

f (x) = 5 - 3 x, at x = \frac{1}{3}

What is (\partial)/(\partial x)(2y^2+3x) ?
The answer to (\partial)/(\partial x)(2y^2+3x) is 3