What is the solution for xy^2+3y^2-x^2y^'=0 ?

The solution for xy^2+3y^2-x^2y^'=0 is y=-x/(xln(x)-3+c_{1)x}

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xy^2+3y^2-x^2y^'=0

x y^{2} + 3 y^{2} - x^{2} y^{^{'}} = 0

y = - \frac{x}{x ln ( x ) - 3 + c _{1} x}

Solution steps

x y^{2} + 3 y^{2} - x^{2} y^{'} (x) = 0

Solve separable ODE:

y = - \frac{x}{x ln ( x ) - 3 + c _{1} x}

y = - \frac{x}{x ln ( x ) - 3 + c _{1} x}

\frac{d}{d x} (\frac{3 x - 2}{2 x - 3})

\int \frac{1}{t ^{\frac{3}{2}}} d t

\int \frac{2}{1 + 4 x ^{2}} d x

\int sin (\frac{1}{2})

z^{3}

What is the solution for xy^2+3y^2-x^2y^'=0 ?
The solution for xy^2+3y^2-x^2y^'=0 is y=-x/(xln(x)-3+c_{1)x}