What is (d^2)/(dx^2)(x^2-y^2) ?

The answer to (d^2)/(dx^2)(x^2-y^2) is 2-2((dy)/(dx)^2+(d^2y)/(dx^2)y)

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(d^2)/(dx^2)(x^2-y^2)

\frac{d ^{2}}{d x ^{2}} (x^{2} - y^{2})

2 - 2 (\frac{d y}{d x}^{2} + \frac{d ^{2} y}{d x ^{2}} y)

Solution steps

\frac{d ^{2}}{d x ^{2}} (x^{2} - y^{2})

\frac{d}{d x} (x^{2} - y^{2}) = 2 x - 2 y \frac{d y}{d x}

= \frac{d}{d x} (2 x - 2 y \frac{d y}{d x})

\frac{d}{d x} (2 x - 2 y \frac{d y}{d x}) = 2 - 2 (\frac{d y}{d x}^{2} + \frac{d ^{2} y}{d x ^{2}} y)

= 2 - 2 (\frac{d y}{d x}^{2} + \frac{d ^{2} y}{d x ^{2}} y)

\frac{d}{d x} (y z (x)^{3})

\frac{\partial}{\partial y} (0)

\frac{d}{d x} (2 e^{2 x} \cdot x)

\int sin (x) + 6 d x

\int \frac{x ^{2} + 6 x - 8}{x ^{3} - 4 x} d x

What is (d^2)/(dx^2)(x^2-y^2) ?
The answer to (d^2)/(dx^2)(x^2-y^2) is 2-2((dy)/(dx)^2+(d^2y)/(dx^2)y)