What is the sum from n=1 to infinity of (n^4)/(4^n) ?

The sum from n=1 to infinity of (n^4)/(4^n) is converges

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sum from n=1 to infinity of (n^4)/(4^n)

n = 1 \sum \infty \frac{n ^{4}}{4 ^{n}}

converges

Solution steps

n = 1 \sum \infty \frac{n ^{4}}{4 ^{n}}

Apply Series Ratio Test:

converges

= converges

x, \frac{1}{x ^{2}}, [0, 1]

\frac{d}{d x} (ln ((1 - x^{2})^{- \frac{1}{2}}))

\frac{1}{1 + s ^{2}}

\int 8 t^{3} - 6 t^{- 2} d t

x \to 5 + lim (\frac{2}{x - 5})

What is the sum from n=1 to infinity of (n^4)/(4^n) ?
The sum from n=1 to infinity of (n^4)/(4^n) is converges