What is the derivative of f(x)=-2xsin(x^2) ?

The derivative of f(x)=-2xsin(x^2) is -2(sin(x^2)+2x^2cos(x^2))

What is the first derivative of f(x)=-2xsin(x^2) ?

The first derivative of f(x)=-2xsin(x^2) is -2(sin(x^2)+2x^2cos(x^2))

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derivative of

f (x) = - 2 x sin (x^{2})

- 2 (sin (x^{2}) + 2 x^{2} cos (x^{2}))

Solution steps

\frac{d}{d x} (- 2 x sin (x^{2}))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 2 \frac{d}{d x} (x sin (x^{2}))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x, g = sin (x^{2})

= - 2 (\frac{d x}{d x} sin (x^{2}) + \frac{d}{d x} (sin (x^{2})) x)

\frac{d x}{d x} = 1

\frac{d}{d x} (sin (x^{2})) = cos (x^{2}) \cdot 2 x

= - 2 (1 \cdot sin (x^{2}) + cos (x^{2}) \cdot 2 xx)

Simplify

- 2 (1 \cdot sin (x^{2}) + cos (x^{2}) \cdot 2 xx) : - 2 (sin (x^{2}) + 2 x^{2} cos (x^{2}))

= - 2 (sin (x^{2}) + 2 x^{2} cos (x^{2}))

\frac{\partial}{\partial c} (\frac{a ^{3} b ^{4}}{c ^{2} d ^{4}})

f (x) = arccos (x)

\frac{d}{d x} (3 x e^{- 3 x})

\frac{\partial}{\partial x} (2 cos (4 x))

e^{e^{t}}

What is the derivative of f(x)=-2xsin(x^2) ?
The derivative of f(x)=-2xsin(x^2) is -2(sin(x^2)+2x^2cos(x^2))
What is the first derivative of f(x)=-2xsin(x^2) ?
The first derivative of f(x)=-2xsin(x^2) is -2(sin(x^2)+2x^2cos(x^2))