What is the solution for y^'=(1.5-0.8y)/(0.5+0.8x) ?

The solution for y^'=(1.5-0.8y)/(0.5+0.8x) is y=-(c_{1})/(0.5+0.8x)+1.875

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y^'=(1.5-0.8y)/(0.5+0.8x)

y^{^{'}} = \frac{1.5 - 0.8 y}{0.5 + 0.8 x}

y = - \frac{c _{1}}{0.5 + 0.8 x} + 1.875

Solution steps

y^{'} (x) = \frac{1.5 - 0.8 y}{0.5 + 0.8 x}

Solve separable ODE:

y = - \frac{c _{1}}{0.5 + 0.8 x} + 1.875

y = - \frac{c _{1}}{0.5 + 0.8 x} + 1.875

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What is the solution for y^'=(1.5-0.8y)/(0.5+0.8x) ?
The solution for y^'=(1.5-0.8y)/(0.5+0.8x) is y=-(c_{1})/(0.5+0.8x)+1.875