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Popular >

y^'=sqrt(x^9+1)

Solution

y^{^{'}} = x^{9} + 1

Solution

y = \int x^{9} + 1 d x

Solution steps

y^{'} (x) = x^{9} + 1

If

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int x^{9} + 1 d x

y = \int x^{9} + 1 d x

Popular Examples

derivative of h(t)=t^2(7t+8)^3 derivative of

h (t) = t^{2} (7 t + 8)^{3}

(d^2)/(dx^2)(7sec(x))

\frac{d ^{2}}{d x ^{2}} (7 sec (x))

(\partial)/(\partial x)(((2+t^2))/(3x-x^3))

\frac{\partial}{\partial x} (\frac{( 2 + t ^{2} )}{3 x - x ^{3}})

derivative of y=e^{2-x}derivative of

y = e^{2 - x}

integral from 0 to 3 of (sqrt(9-x^2))

\int_{0}^{3} (9 - x^{2}) d x

Frequently Asked Questions (FAQ)

What is the solution for y^'=sqrt(x^9+1) ?
The solution for y^'=sqrt(x^9+1) is y=integral of sqrt(x^9+1)