What is the d/(da)((tan^2(a)-sin^2(a))/(tan^2(a))) ?

The d/(da)((tan^2(a)-sin^2(a))/(tan^2(a))) is (-sin(2a)+2tan(a))/(tan^2(a))

What is the first d/(da)((tan^2(a)-sin^2(a))/(tan^2(a))) ?

The first d/(da)((tan^2(a)-sin^2(a))/(tan^2(a))) is (-sin(2a)+2tan(a))/(tan^2(a))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d a} (\frac{tan ^{2} ( a ) - sin ^{2} ( a )}{tan ^{2} ( a )})

\frac{- sin ( 2 a ) + 2 tan ( a )}{tan ^{2} ( a )}

Solution steps

\frac{d}{d a} (\frac{tan ^{2} ( a ) - sin ^{2} ( a )}{tan ^{2} ( a )})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d a} ( tan ^{2} ( a ) - sin ^{2} ( a ) ) tan ^{2} ( a ) - \frac{d}{d a} ( tan ^{2} ( a ) ) ( tan ^{2} ( a ) - sin ^{2} ( a ) )}{( tan ^{2} ( a ) ) ^{2}}

\frac{d}{d a} (tan^{2} (a) - sin^{2} (a)) = 2 tan (a) sec^{2} (a) - sin (2 a)

\frac{d}{d a} (tan^{2} (a)) = 2 tan (a) sec^{2} (a)

= \frac{( 2 tan ( a ) sec ^{2} ( a ) - sin ( 2 a ) ) tan ^{2} ( a ) - 2 tan ( a ) sec ^{2} ( a ) ( tan ^{2} ( a ) - sin ^{2} ( a ) )}{( tan ^{2} ( a ) ) ^{2}}

Simplify

\frac{( 2 tan ( a ) sec ^{2} ( a ) - sin ( 2 a ) ) tan ^{2} ( a ) - 2 tan ( a ) sec ^{2} ( a ) ( tan ^{2} ( a ) - sin ^{2} ( a ) )}{( tan ^{2} ( a ) ) ^{2}} : \frac{- sin ( 2 a ) + 2 tan ( a )}{tan ^{2} ( a )}

= \frac{- sin ( 2 a ) + 2 tan ( a )}{tan ^{2} ( a )}

\frac{d}{d x} (8 x y - \frac{1}{4} (x + y)^{4})

f (x) = x^{2} cos (x^{2})

\frac{d y}{d x}, y = - x

\int \frac{ln ( x ^{3} )}{x} d x

x \to 2 lim (\frac{2 - ∣ x ∣}{2 + x})

What is the d/(da)((tan^2(a)-sin^2(a))/(tan^2(a))) ?
The d/(da)((tan^2(a)-sin^2(a))/(tan^2(a))) is (-sin(2a)+2tan(a))/(tan^2(a))
What is the first d/(da)((tan^2(a)-sin^2(a))/(tan^2(a))) ?
The first d/(da)((tan^2(a)-sin^2(a))/(tan^2(a))) is (-sin(2a)+2tan(a))/(tan^2(a))