What is the derivative of (2w^3-w)/w ?

The derivative of (2w^3-w)/w is 4w

What is the first derivative of (2w^3-w)/w ?

The first derivative of (2w^3-w)/w is 4w

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

\frac{2 w ^{3} - w}{w}

4 w

Solution steps

\frac{d}{d w} (\frac{2 w ^{3} - w}{w})

Simplify

\frac{2 w ^{3} - w}{w} : 2 w^{2} - 1

= \frac{d}{d w} (2 w^{2} - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d w} (2 w^{2}) - \frac{d}{d w} (1)

\frac{d}{d w} (2 w^{2}) = 4 w

\frac{d}{d w} (1) = 0

= 4 w - 0

Simplify

= 4 w

\int t (t^{2} + 1)^{5} d t

n = 0 \sum \infty \frac{n - 1}{n ^{2}}

\int 1 + e^{t} d t

y^{^{''}} + 0.1 y^{^{'}} + 0.0004 y = 0

f (x) = \frac{x - 6}{x + 2}, at x = 2

What is the derivative of (2w^3-w)/w ?
The derivative of (2w^3-w)/w is 4w
What is the first derivative of (2w^3-w)/w ?
The first derivative of (2w^3-w)/w is 4w