What is the derivative of x^2*3y ?

The derivative of x^2*3y is 3(2xy+(dy)/(dx)x^2)

What is the first derivative of x^2*3y ?

The first derivative of x^2*3y is 3(2xy+(dy)/(dx)x^2)

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\frac{d}{d x} (x^{2} \cdot 3 y)

3 (2 x y + \frac{d y}{d x} x^{2})

Solution steps

\frac{d}{d x} (x^{2} \cdot 3 y)

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d x} (x^{2} y)

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x^{2}, g = y

= 3 (\frac{d}{d x} (x^{2}) y + \frac{d y}{d x} x^{2})

\frac{d}{d x} (x^{2}) = 2 x

= 3 (2 x y + \frac{d y}{d x} x^{2})

\int 4 r^{2} + 1 d r

\int_{- \frac{1}{2}}^{0} (\frac{1}{2} + 2 y + 3 z) d y

\frac{\partial}{\partial x} (e^{x s i n (y)})

1 + 2 x

x \to 2 lim (\frac{3 x + 4}{8 x - 1})

What is the derivative of x^2*3y ?
The derivative of x^2*3y is 3(2xy+(dy)/(dx)x^2)
What is the first derivative of x^2*3y ?
The first derivative of x^2*3y is 3(2xy+(dy)/(dx)x^2)