What is the derivative of-(x^4/4) ?

The derivative of-(x^4/4) is -x^3

What is the first derivative of-(x^4/4) ?

The first derivative of-(x^4/4) is -x^3

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\frac{d}{d x} (- \frac{x ^{4}}{4})

- x^{3}

Solution steps

\frac{d}{d x} (- \frac{x ^{4}}{4})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{1}{4} \frac{d}{d x} (x^{4})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - \frac{1}{4} \cdot 4 x^{4 - 1}

Simplify

- \frac{1}{4} \cdot 4 x^{4 - 1} : - x^{3}

= - x^{3}

\frac{d y}{y ^{3}} = x^{- 2} d x

\int \frac{3 ^{x}}{1 + 9 ^{x}} d x

- \frac{12}{x ^{5}}

f (x) = - 3 x^{2} - 4 x

\frac{d}{d y} (\frac{1 - cos ( y )}{1 - cos ( 2 y )})

What is the derivative of-(x^4/4) ?
The derivative of-(x^4/4) is -x^3
What is the first derivative of-(x^4/4) ?
The first derivative of-(x^4/4) is -x^3