What is the derivative of ln(x-2x^2) ?

The derivative of ln(x-2x^2) is 1/x-4x

What is the first derivative of ln(x-2x^2) ?

The first derivative of ln(x-2x^2) is 1/x-4x

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\frac{d}{d x} (ln (x) - 2 x^{2})

\frac{1}{x} - 4 x

Solution steps

\frac{d}{d x} (ln (x) - 2 x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (ln (x)) - \frac{d}{d x} (2 x^{2})

\frac{d}{d x} (ln (x)) = \frac{1}{x}

\frac{d}{d x} (2 x^{2}) = 4 x

= \frac{1}{x} - 4 x

\frac{d}{d x} (\frac{5 x}{x ^{2} + 1})

e^{y x^{2}}

\frac{d}{d x} ((3 x - 4)^{2})

\frac{d}{d x} (x (12 - 2 x)^{2})

\int 8 e^{4 x} cos (6 x) d x

What is the derivative of ln(x-2x^2) ?
The derivative of ln(x-2x^2) is 1/x-4x
What is the first derivative of ln(x-2x^2) ?
The first derivative of ln(x-2x^2) is 1/x-4x