What is the derivative of ln(x^2-8x) ?

The derivative of ln(x^2-8x) is (2x-8)/(x^2-8x)

What is the first derivative of ln(x^2-8x) ?

The first derivative of ln(x^2-8x) is (2x-8)/(x^2-8x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (ln (x^{2} - 8 x))

\frac{2 x - 8}{x ^{2} - 8 x}

Solution steps

\frac{d}{d x} (ln (x^{2} - 8 x))

Apply the chain rule:

\frac{1}{x ^{2} - 8 x} \frac{d}{d x} (x^{2} - 8 x)

= \frac{1}{x ^{2} - 8 x} \frac{d}{d x} (x^{2} - 8 x)

\frac{d}{d x} (x^{2} - 8 x) = 2 x - 8

= \frac{1}{x ^{2} - 8 x} (2 x - 8)

Simplify

\frac{1}{x ^{2} - 8 x} (2 x - 8) : \frac{2 x - 8}{x ^{2} - 8 x}

= \frac{2 x - 8}{x ^{2} - 8 x}

x \to π lim (cos (tan (x)))

x \to \infty lim (x^{10})

\int x^{2} ln (x + 1) d x

\frac{d}{d x} (e^{2 x} + 4 e^{- 4 x} + 1)

\int_{1}^{2} \frac{13}{x ^{3} + 4 x} d x

What is the derivative of ln(x^2-8x) ?
The derivative of ln(x^2-8x) is (2x-8)/(x^2-8x)
What is the first derivative of ln(x^2-8x) ?
The first derivative of ln(x^2-8x) is (2x-8)/(x^2-8x)