What is the tangent of f(x)=xsqrt(x),(16,64) ?

The tangent of f(x)=xsqrt(x),(16,64) is y=6x-32

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tangent of f(x)=xsqrt(x),(16,64)

tangent of

f (x) = x x, (16, 64)

y = 6 x - 32

Solution steps

Find the slope of

f (x) = x x : \frac{df ( x )}{d x} = \frac{3 x}{2}

Compute the slope of

f (x) = x x

(16, 64) : m = 6

Find the line with slope m=

6

and passing through

(16, 64) : y = 6 x - 32

y = 6 x - 32

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\frac{1}{y} \frac{d y}{d x} = \frac{2}{x}

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What is the tangent of f(x)=xsqrt(x),(16,64) ?
The tangent of f(x)=xsqrt(x),(16,64) is y=6x-32