What is the derivative of ln(4x+1) ?

The derivative of ln(4x+1) is 4/(4x+1)

What is the first derivative of ln(4x+1) ?

The first derivative of ln(4x+1) is 4/(4x+1)

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derivative of

ln (4 x + 1)

\frac{4}{4 x + 1}

Solution steps

\frac{d}{d x} (ln (4 x + 1))

Apply the chain rule:

\frac{1}{4 x + 1} \frac{d}{d x} (4 x + 1)

= \frac{1}{4 x + 1} \frac{d}{d x} (4 x + 1)

\frac{d}{d x} (4 x + 1) = 4

= \frac{1}{4 x + 1} \cdot 4

Simplify

\frac{1}{4 x + 1} \cdot 4 : \frac{4}{4 x + 1}

= \frac{4}{4 x + 1}

3 x^{2} - 4 x + 1

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\int (- 7 - 7 tan^{2} (θ)) d θ

What is the derivative of ln(4x+1) ?
The derivative of ln(4x+1) is 4/(4x+1)
What is the first derivative of ln(4x+1) ?
The first derivative of ln(4x+1) is 4/(4x+1)