What is the derivative of 3cos(x-2e^{2x}) ?

The derivative of 3cos(x-2e^{2x}) is -3sin(x)-4e^{2x}

What is the first derivative of 3cos(x-2e^{2x}) ?

The first derivative of 3cos(x-2e^{2x}) is -3sin(x)-4e^{2x}

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\frac{d}{d x} (3 cos (x) - 2 e^{2 x})

- 3 sin (x) - 4 e^{2 x}

Solution steps

\frac{d}{d x} (3 cos (x) - 2 e^{2 x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 cos (x)) - \frac{d}{d x} (2 e^{2 x})

\frac{d}{d x} (3 cos (x)) = - 3 sin (x)

\frac{d}{d x} (2 e^{2 x}) = 4 e^{2 x}

= - 3 sin (x) - 4 e^{2 x}

f (x) = x^{3} - 2 x + 1, at x = - 1

(e^{x} - e^{- x}) \frac{d y}{d x} = y^{2}

\frac{\partial}{\partial x} (- 10 x + 7 y^{5})

\frac{d}{d x} (\frac{1}{4 x ^{3}} - \frac{6}{5 x ^{4}})

\frac{d y}{d x} = (\frac{2 y + 5}{8 x + 7})^{2}

What is the derivative of 3cos(x-2e^{2x}) ?
The derivative of 3cos(x-2e^{2x}) is -3sin(x)-4e^{2x}
What is the first derivative of 3cos(x-2e^{2x}) ?
The first derivative of 3cos(x-2e^{2x}) is -3sin(x)-4e^{2x}