What is the tangent of 3x-2sqrt(x) ?

The tangent of 3x-2sqrt(x) is y=(3-1/(sqrt(a_{0))})x-sqrt(a_{0)}

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tangent of 3x-2sqrt(x)

tangent of

3 x - 2 x

y = (3 - \frac{1}{a _{0}}) x - a_{0}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, 3 a_{0} - 2 a_{0})

Find the slope of

y = 3 x - 2 x : \frac{d y}{d x} = 3 - \frac{1}{x}

Compute the slope of

y = 3 x - 2 x

x = a_{0} : m = 3 - \frac{1}{a _{0}}

Find the line with slope m=

3 - \frac{1}{a _{0}}

and passing through

(a_{0}, 3 a_{0} - 2 a_{0}) : y = (3 - \frac{1}{a _{0}}) x - a_{0}

y = (3 - \frac{1}{a _{0}}) x - a_{0}

n = 1 \sum \infty \frac{1}{cos ( n )}

\int - 6 sin (2 x) d x

\int_{0}^{3} x 11 - x^{2} d x

\frac{d}{d x} ((\frac{2}{5})^{x})

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What is the tangent of 3x-2sqrt(x) ?
The tangent of 3x-2sqrt(x) is y=(3-1/(sqrt(a_{0))})x-sqrt(a_{0)}