What is the tangent of f(x)=5x-4x^2,(-2,-26) ?

The tangent of f(x)=5x-4x^2,(-2,-26) is y=21x+16

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tangent of f(x)=5x-4x^2,(-2,-26)

tangent of

f (x) = 5 x - 4 x^{2}, (- 2, - 26)

y = 21 x + 16

Solution steps

Find the slope of

f (x) = 5 x - 4 x^{2} : \frac{df ( x )}{d x} = 5 - 8 x

Compute the slope of

f (x) = 5 x - 4 x^{2}

(- 2, - 26) : m = 21

Find the line with slope m=

21

and passing through

(- 2, - 26) : y = 21 x + 16

y = 21 x + 16

\int 3 x + 4 d x

\int sin^{2} (x) cos (x) d x

\int \frac{x + 6}{x + 1} d x

\int \frac{x + 1}{12} d x

\int 3 x^{2} d x

What is the tangent of f(x)=5x-4x^2,(-2,-26) ?
The tangent of f(x)=5x-4x^2,(-2,-26) is y=21x+16