What is the derivative of (x+y^2) ?

The derivative of (x+y^2) is 2(x+y)(1+(dy)/(dx))

What is the first derivative of (x+y^2) ?

The first derivative of (x+y^2) is 2(x+y)(1+(dy)/(dx))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} ((x + y)^{2})

2 (x + y) (1 + \frac{d y}{d x})

Solution steps

\frac{d}{d x} ((x + y)^{2})

Apply the chain rule:

2 (x + y) \frac{d}{d x} (x + y)

= 2 (x + y) \frac{d}{d x} (x + y)

\frac{d}{d x} (x + y) = 1 + \frac{d y}{d x}

= 2 (x + y) (1 + \frac{d y}{d x})

\int_{0}^{1} 1 + 9 x^{2} d x

\int - \frac{1}{cos ^{2} ( x )} d x

\frac{d}{d x} (\frac{6 - 2 x}{x ^{2} - 4})

\frac{d}{d x} (d - \frac{d}{x ^{2}} - a x - b)

\frac{d}{d x} (\frac{1 + cos ( 2 x )}{2})

What is the derivative of (x+y^2) ?
The derivative of (x+y^2) is 2(x+y)(1+(dy)/(dx))
What is the first derivative of (x+y^2) ?
The first derivative of (x+y^2) is 2(x+y)(1+(dy)/(dx))