What is (\partial)/(\partial z)(xe^{-y}-z) ?

The answer to (\partial)/(\partial z)(xe^{-y}-z) is -1

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(\partial)/(\partial z)(xe^{-y}-z)

\frac{\partial}{\partial z} (x e^{- y} - z)

- 1

Solution steps

\frac{\partial}{\partial z} (x e^{- y} - z)

Treat

x, y

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial z} (x e^{- y}) - \frac{\partial}{\partial z} (z)

\frac{\partial}{\partial z} (x e^{- y}) = 0

\frac{\partial}{\partial z} (z) = 1

= 0 - 1

Simplify

= - 1

f (x) = cos (arctan (x))

x \to 0 lim ((\frac{x ^{2}}{2}) - x)

\frac{s - 2}{s + 4}

n = 1 \sum \infty 2 (\frac{3}{4})^{n}

\frac{sec ^{2} ( x )}{4}, 4 cos^{2} (x)

What is (\partial)/(\partial z)(xe^{-y}-z) ?
The answer to (\partial)/(\partial z)(xe^{-y}-z) is -1