What is the first derivative of ln(e^2) ?

The first derivative of ln(e^2) is 0

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derivative of ln(e^2)

\frac{d}{d x} (ln (e^{2}))

0

Solution steps

\frac{d}{d x} (ln (e^{2}))

ln (e^{2}) = 2

= \frac{d}{d x} (2)

Derivative of a constant:

\frac{d}{d x} (a) = 0

= 0

\int_{0}^{3} (2 x + 1) d x

y^{^{''}} + 16 y = 16 sin (4 t)

\int \frac{1}{cos ^{2} ( 2 y )} d y

f (x) = 14 (2 x + 5)^{6}

\frac{\partial}{\partial y} (\frac{y ^{3}}{x})