What is the derivative of f(x)=sqrt(x)+1 ?

The derivative of f(x)=sqrt(x)+1 is 1/(2sqrt(x))

What is the first derivative of f(x)=sqrt(x)+1 ?

The first derivative of f(x)=sqrt(x)+1 is 1/(2sqrt(x))

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derivative of

f (x) = x + 1

\frac{1}{2 x}

Solution steps

\frac{d}{d x} (x + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x) + \frac{d}{d x} (1)

\frac{d}{d x} (x) = \frac{1}{2 x}

\frac{d}{d x} (1) = 0

= \frac{1}{2 x} + 0

Simplify

= \frac{1}{2 x}

\frac{d x}{x ( y - 1 )} + \frac{d y}{y ( x + 2 )} = 0, y (1) = 1

11 x - 4 y x^{2} + 1 y^{^{'}} = 0, y (0) = 7

x \to 5 lim (\frac{4}{x - 5})

\frac{s ^{3} + 5 s ^{2} + 9 s + 7}{( s + 1 ) \cdot ( s + 2 )}

\frac{( x ^{2} - 6 ) ^{3}}{x ^{2} + 2}

What is the derivative of f(x)=sqrt(x)+1 ?
The derivative of f(x)=sqrt(x)+1 is 1/(2sqrt(x))
What is the first derivative of f(x)=sqrt(x)+1 ?
The first derivative of f(x)=sqrt(x)+1 is 1/(2sqrt(x))