What is the integral of ((ln^2(x)))/x ?

The integral of ((ln^2(x)))/x is (ln^3(x))/3+C

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integral of ((ln^2(x)))/x

\int \frac{( ln ^{2} ( x ) )}{x} d x

\frac{ln ^{3} ( x )}{3} + C

Solution steps

\int \frac{ln ^{2} ( x )}{x} d x

Apply u-substitution

: \int u^{2} d u

= \int u^{2} d u

Apply the Power Rule

: \frac{u ^{3}}{3}

= \frac{u ^{3}}{3}

Substitute back

u = ln (x)

= \frac{ln ^{3} ( x )}{3}

Add a constant to the solution

= \frac{ln ^{3} ( x )}{3} + C

\frac{d}{d x} (e^{- 2 x} cos (3 x) + sin (3 x))

\int x e^{2 x} sin (3 x) d x

\frac{2}{s ^{2} + 2 s + 1}

\frac{( z ^{n} )}{n !}

\int \frac{2 x}{3 x ^{2} - 1} d x

What is the integral of ((ln^2(x)))/x ?
The integral of ((ln^2(x)))/x is (ln^3(x))/3+C