What is the tangent of y=4x^3-2x,(1,2) ?

The tangent of y=4x^3-2x,(1,2) is y=10x-8

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tangent of y=4x^3-2x,(1,2)

tangent of

y = 4 x^{3} - 2 x, (1, 2)

y = 10 x - 8

Solution steps

Find the slope of

y = 4 x^{3} - 2 x : \frac{d y}{d x} = 12 x^{2} - 2

Compute the slope of

y = 4 x^{3} - 2 x

(1, 2) : m = 10

Find the line with slope m=

10

and passing through

(1, 2) : y = 10 x - 8

y = 10 x - 8

f (x) = x^{2} + 1, (- 4, 17)

2 x y + x^{2} \frac{d y}{d x} = y^{2}

\frac{z ^{\frac{8}{3}}}{8} - \frac{e ^{- 2 z}}{2}

\frac{d}{d x} (\frac{3 x + 4}{2 x - 5})

y^{^{''}} - 3 y^{^{'}} = 0

What is the tangent of y=4x^3-2x,(1,2) ?
The tangent of y=4x^3-2x,(1,2) is y=10x-8