What is (\partial)/(\partial x)(5x^2y-1) ?

The answer to (\partial)/(\partial x)(5x^2y-1) is 10xy

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(\partial)/(\partial x)(5x^2y-1)

\frac{\partial}{\partial x} (5 x^{2} y - 1)

10 x y

Solution steps

\frac{\partial}{\partial x} (5 x^{2} y - 1)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (5 x^{2} y) - \frac{\partial}{\partial x} (1)

\frac{\partial}{\partial x} (5 x^{2} y) = 10 y x

\frac{\partial}{\partial x} (1) = 0

= 10 y x - 0

Simplify

= 10 x y

f (x) = \frac{- 4 x}{x ^{2} + 1}, (1, 2)

\int \frac{3}{2 x - 1} d x

y^{^{''}} + 4 y = 8 t^{2} - 20 t + 8

\frac{d}{d x} (4 x^{3} + \frac{1}{x ^{2}} - x + 3)

\frac{d}{d x} (\frac{5 x}{( x ^{3} - 6 ) ^{2}})

What is (\partial)/(\partial x)(5x^2y-1) ?
The answer to (\partial)/(\partial x)(5x^2y-1) is 10xy