What is the integral of (sin(θ))/(cos^2(θ)-cos(θ)-2) ?

The integral of (sin(θ))/(cos^2(θ)-cos(θ)-2) is 1/3 (ln| 2/3+2/3 cos(θ)|-ln|-4/3+2/3 cos(θ)|)+C

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integral of (sin(θ))/(cos^2(θ)-cos(θ)-2)

\int \frac{sin ( θ )}{cos ^{2} ( θ ) - cos ( θ ) - 2} d θ

\frac{1}{3} (ln \frac{2}{3} + \frac{2}{3} cos (θ) - ln - \frac{4}{3} + \frac{2}{3} cos (θ)) + C

Solution steps

\int \frac{sin ( θ )}{cos ^{2} ( θ ) - cos ( θ ) - 2} d θ

Apply u-substitution

: \int - \frac{1}{u ^{2} - u - 2} d u

= \int - \frac{1}{u ^{2} - u - 2} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int \frac{1}{u ^{2} - u - 2} d u

Complete the square

u^{2} - u - 2 : (u - \frac{1}{2})^{2} - \frac{9}{4}

= - \int \frac{1}{( u - \frac{1}{2} ) ^{2} - \frac{9}{4}} d u

Apply u-substitution

: \int \frac{4}{4 v ^{2} - 9} d v

= - \int \frac{4}{4 v ^{2} - 9} d v

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 4 \cdot \int \frac{1}{4 v ^{2} - 9} d v

Apply Integral Substitution

= - 4 \cdot \int \frac{1}{6 ( w ^{2} - 1 )} d w

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 4 \cdot \frac{1}{6} \cdot \int \frac{1}{w ^{2} - 1} d w

Factor

w^{2} - 1 : - (- w^{2} + 1)

= - 4 \cdot \frac{1}{6} \cdot \int \frac{1}{- ( - w ^{2} + 1 )} d w

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 4 \cdot \frac{1}{6} (- \int \frac{1}{- w ^{2} + 1} d w)

Use the common integral:

\int \frac{1}{- w ^{2} + 1} d w = \frac{ln ∣ w + 1 ∣}{2} - \frac{ln ∣ w - 1 ∣}{2}

= - 4 \cdot \frac{1}{6} (- (\frac{ln ∣ w + 1 ∣}{2} - \frac{ln ∣ w - 1 ∣}{2}))

Substitute back

= - 4 \cdot \frac{1}{6} (- (\frac{ln \frac{2}{3} ( cos ( θ ) - \frac{1}{2} ) + 1}{2} - \frac{ln \frac{2}{3} ( cos ( θ ) - \frac{1}{2} ) - 1}{2}))

Simplify

- 4 \cdot \frac{1}{6} (- (\frac{ln \frac{2}{3} ( cos ( θ ) - \frac{1}{2} ) + 1}{2} - \frac{ln \frac{2}{3} ( cos ( θ ) - \frac{1}{2} ) - 1}{2})) : \frac{1}{3} (ln \frac{2}{3} + \frac{2}{3} cos (θ) - ln - \frac{4}{3} + \frac{2}{3} cos (θ))

= \frac{1}{3} (ln \frac{2}{3} + \frac{2}{3} cos (θ) - ln - \frac{4}{3} + \frac{2}{3} cos (θ))

Add a constant to the solution

= \frac{1}{3} (ln \frac{2}{3} + \frac{2}{3} cos (θ) - ln - \frac{4}{3} + \frac{2}{3} cos (θ)) + C

y (θ) = cos (θ^{2})

x \to \infty lim (2 x^{4})

\frac{d y}{d x} = 2 y - x y

(- 4 x^{2} + 1)^{2}

x \to 1 + lim (\frac{3}{x} - \frac{2}{ln ( x )})

What is the integral of (sin(θ))/(cos^2(θ)-cos(θ)-2) ?
The integral of (sin(θ))/(cos^2(θ)-cos(θ)-2) is 1/3 (ln| 2/3+2/3 cos(θ)|-ln|-4/3+2/3 cos(θ)|)+C