What is the limit as x approaches 0 of 1-cos(2x) ?

The limit as x approaches 0 of 1-cos(2x) is 0

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limit as x approaches 0 of 1-cos(2x)

x \to 0 lim (1 - cos (2 x))

0

Solution steps

x \to 0 lim (1 - cos (2 x))

Plug in the value

x = 0

= 1 - cos (2 \cdot 0)

Simplify

1 - cos (2 \cdot 0) : 0

= 0

\int \frac{8}{9} x^{- \frac{1}{9}} d x

x \to 3 lim (3 x)

\int \frac{1}{9} x^{2} d x

\frac{d}{d x} (\frac{( 4 x ^{3} + 2 x ^{2} )}{sin ( x )})^{2}

y = \frac{- 2 x ^{2} + 3 x - 15}{x ^{3} - 9 x}, x = 1, x = 2

What is the limit as x approaches 0 of 1-cos(2x) ?
The limit as x approaches 0 of 1-cos(2x) is 0